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* NAME: AB16-CCT4 DOC 70180658000 REV H PAGE 75

3539 06302 000000 BSZ 1 3540 06303 010003 STAQ S STACK HAS ADDR OF X6AA 3541 06304 -0 02 00003 LDA* 3 TESTING LDA* 3 3542 06305 0 06 06301 ADD *-4 3543 06306 100040 SZE 3544 06307 000000 HLT LDA* 3 FAILED 3545 * 3546 06310 024003 POP STACK HAS ADDR OF X6AA+1 3547 06311 004003 LDAQ S 3548 06312 0 04 06302 STA X6AA+2 3549 06313 024003 POP 3550 06314 024003 POP STACK HAS ADDR OF X6AA+3 3551 06315 -0 02 00004 LDA* 4 TESTING LDA* 4 S=X6AA+2 3552 06316 0 06 06300 ADD X6AA 3553 06317 100040 SZE 3554 06320 000000 HLT LDA* 4 FAILED 3555 * 3556 06321 -0 02 00005 LDA* 5 ADDR IS X6AA+2 AND STACK GOES TO X6AA+3 3557 06322 0 06 06300 ADD X6AA 3558 06323 100040 SZE 3559 06324 000000 HLT LDA* 5 FAILED 3560 * 3561 * 3562 * 3563 * TEST JMP 4 AND JMP 5 3564 * 3565 06325 101000 NOP 3566 06326 0 10 06327 JST *+1 FIND A REFERENCE LOC IN THE SAME SECTOR 3567 06327 0 000000 DAC ** 3568 06330 101000 NOP 3569 06331 0 02 06327 LDA *-2 3570 06332 0 03 06743 ANA ='37777 STRIP BITS 1 AND 2 3571 06333 0 06 06740 ADD ='13 3572 06334 0 04 00003 STA 3 STACK IS N2 3573 * 3574 06335 0 01 00004 JMP 4 FIRST JMP 4 - S=N2-1 3575 06336 000000 HLT 3576 06337 0 01 06343 JMP *+4 3577 06340 0 01 00004 JMP 4 THIRD JMP 4 - S=N2-3 3578 06341 0 01 00004 JMP 4 SECOND JMP 4 - S=N2-2 3579 06342 000000 N2 HLT 3580 06343 101000 NOP 3581 06344 004003 LDAQ S 3582 06345 0 06 06737 ADD ='12 3583 06346 010003 STAQ S STACK IS N3 3584 06347 0 01 00005 JMP 5 FIRST JMP 5, ADDR IS N3, S=N3+1 3585 06350 000000 HLT 3586 06351 0 01 00005 N3 JMP 5 SECOND JMP 5 - ADDR=N3+1 AND S=N3+2 3587 06352 100000 SKP 3588 06353 000000 HLT
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